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The mass of a .(3)^(7) Li nucleus is 0.0...

The mass of a `._(3)^(7) Li` nucleus is `0.042 u` less than the sum of the masses of all its nucleons. The binding energy per nucleon of `._(3)^(7)Li` nucleus is nearly

A

46 MeV

B

5.6 MeV

C

3.9 MeV

D

23 MeV

Text Solution

Verified by Experts

For `""_(3)^(7)Li` nucleus,
Mass defect, `DeltaM=0.042u`
`because" "1u=931.5MeV//c^(2)`
`therefore" "DeltaM=0.042xx931.5MeV//c^(2)=39.1MeV//c^(2)`
Binding energy,
`E_(b)=DeltaMc^(2)=(39.1(MeV)/(c^(2)))c^(2)39.1MeV`
Binding energy per nucleon,
`E_(bn)=(E_(b))/(A)=(39.1MeV)/(7)~~ 5.6 MeV`
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Knowledge Check

  • The mass of a ._(3)^(7)Li nucleus is 0.042 u less than the sum of the masses of all its nucleous. The binding energy per nucleon of ._(3)^(7) Li nucleus nearly

    A
    46 MeV
    B
    5.6 MeV
    C
    3.9 MeV
    D
    23 MeV

  • The mass of a a_3^7 Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ._3^7 Li nucleus is nearly.

    A
    46 MeV
    B
    5.6 MeV
    C
    3.9 MeV
    D
    23 MeV

  • The mass of ._3^7Li is 0.042 amu less than the sum of masses of its constituents. The binding energy per nucleon is

    A
    5.586 MeV
    B
    10.522 MeV
    C
    2.433 MeV
    D
    3.739 MeV

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