The decay constant of radio isotope is `lambda`. If `A_(1) and A_(2)` are its activities at times `t_(1) and t_(2)` respectively, the number of nuclei which have decayed during the time `(t_(1)-t_(2))`

Options

A. `A_(1)t_(1)-A_(2)t_(2)`
B. `A_(1)-A_(2)`
C. `(A_(1)-A_(2))//lambda`
D. `lambda(A_(1)-A_(2))`

Explanation

`A_(1)=lambdaN_(1)` at time `t_(1), A_(2)=lambdaN_(2)` at time `t_(2)`
Therefore, numb er of nucleus of mass m moving with velocity v
`"or "d=(2Ze^(2))/(4piepsilon_(0)((1)/(2)mv^(2))) therefore d prop (1)/(m)`