The power obtained in a reactor using `U^(235)` disintergration is `1000kW`. The mass decay of `U^(235)` per hour is

Options

A. 10 microgram
B. 20 microgram
C. 40 microgram
D. 1 microgram

Explanation

According to Einstein.s mass energy relation
`E=mc^(2) or m=(E)/(c^(2))`
Mass decay per second
`=(Deltam)/(Deltat)=(1)/(c^(2))(DeltaE)/(Deltat)=(P )/(c^(2))=(1000xx10^(3)W)/((3xx10^(8)m//s)^(2))=(10^(6))/(9xx10^(16))kg//s`
Mass decay per hour
`=(Deltam)/(Deltat)xx60xx60=((10^(6))/(9xx10^(16))kg//s)(3600s)`
`=4xx10^(-8)kg=40xx10^(-6)g=40mug`