If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :

Options

A. 2.4
B. 1.2
C. 4.8
D. 3.6

Explanation

Nuclear radius, `R=R_(0)A^(1//3)`
where `R_(0)` is a constant and A is the mass number
`therefore" "(R_(Al))/(R_(Cu))=((27)^(1//3))/((64)^(1//3))=(3)/(4)`
`"or "R_(Cu)=(4)/(3)xxR_(Al)=(4)/(3)xx"3.6 fermi = 4.8 fermi"`