If radius of the `._(13)^(27)Al` nucleus is taken to be `R_(AI)`, then the radius of `._(53)^(125)Te` nucleus is nearly

Options

A. `(3)/(5)R_(Al)`
B. `((13)/(53))^(1//3)R_(Al`
C. `((53)/(13))^(1//3)R_(Al)`
D. `(5)/(3)R_(Al)`

Explanation

Radius of the nucleus `R=R_(0)A^(1//3)`
`(R_(Al))/(R_(Te))=((A_(Al))/(A_(Te)))^(1//3)`
Here, `A_(Al)=27, A_(Te)=125, R_(Te)=?`
`(R_(Al))/(R_(Te))=((27)/(125))^(1//3)=(3)/(5)rArr R_(Te)=(5)/(3)R_(Al)`