When an `alpha-`particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on `m` as :

Options

A. `(1)/(m^(2))`
B. m
C. `(1)/(m)`
D. `(1)/(sqrtm)`

Explanation

Distance of closes approach when an `alpha-` particle of mass m moving with velocity v is bombarded on a heavy nuclelus of charge Ze, is given by
`r_(0)=(Ze^(2))/(pi epsilon_(0)mv^(2))" "therefore" "r_(0)=(1)/(m)`