The ratio of wavelength of the lest line of Balmer series and the last line Lyman series is:

Options

A. 1
B. 4
C. 0.5
D. 2

Explanation

The wavelength of last line of Balmer series
`(1)/(lambda_(B))=Rc((1)/(2^(2))-(1)/(oo^(2)))=(Rc )/(4)`
The wavelength of last line of Lyman series
`(1)/(lambda_(L))=Rc((1)/(1^(2))-(1)/(oo^(2)))=Rc`
`(1)/(lambda_(L))=Rc((1)/(1^(2))-(1)/(oo^(2)))=Rc`
`therefore" "(lambda_(B))/(lambda_(L))=(4)/(1)=4`