[" 5."0.116g" of "C_(4)H_(4)O_(4)" ( "A" ) is neutralised by "0.074g" of "],[Ca(OH)" 2.Hence,protonic hydrogen "(H^(o+))" in (A) will "],[" be "]

0.116 g of C_(4)H_(4)O_(4) (A) in neutralised by 0.074 g of Ca(OH)_(2) . Hence protonic hydrogen (H^(o+)) in (A) will be

0.116 g of C_(4)H_(4)O_(4) (A) in neutralised by 0.074 g of Ca(OH)_(2) . Hence protonic hydrogen (H^(o+)) in (A) will be

1 g of an acid C_(6)H_(10)O_(4) is completely neutralised by 0.768 g KOH . Calculate the number of neutralizable protons in acid.

NaHC_(2)O_(4) is 0.1 M when neutralised with NaOH. Hence, it is ...... when oxidised with MnO_(4-)//H^(+) .

One gram of the acid C_(6) H_(10) O_(4) requires 0.768 g of KOH for complete neutralisation. How many neutralisable hydrogen atoms are in this molecule?

One gram of the acid C_(6) H_(10) O_(4) requires 0.768 g of KOH for complete neutralisation. How many neutralisable hydrogen atoms are in this molecule?

100 " mL of " 0.2 M Kal (OH)_(2)CO_(3) solution is completely neutralised by a standard solution of (M)/(4)H_(2)C_(2)O_(4) . Which of the following is/are wrong?

100 " mL of " 0.2 M Kal (OH)_(2)CO_(3) solution is completely neutralised by a standard solution of (M)/(4)H_(2)C_(2)O_(4) . Which of the following is/are wrong?