An electron is at rest. Its wavelength is

The wavelength of a photon is 1.4 Å . It collides with an electron. Its wavelength after collision is 2.0 Å . Calculate the energy of the scattered electron.

The speed of an electron having its wavelength being equal to speed can vbegiven by :

The de Broglie wavelength associated with an electron is 4overset@A . Its momentum is

The energy that should be added to an electron to reduce its de Broglie wavelength from lamda " to " lamda/2 is (Considering E to the energy of electron when its de Broglie wavelength is lamda )

Electrons used in electron microscope are of the wavelength

Nomination of electron is 5200 A .At which velocity of electron its wavelength is equal to photon.

The rest energy of an electron is 0.511 MeV. The electron is accelerated from rest to a velocity 0.5 c. The change in its energy will be

If the KE of free electron triples, its deBroglie wavelength changes by a factor