The focal chord of `y^(2)=16x` is tangent to `(x-6)^(2)+y^(2)=2`.
Then the possible value of the square of slope of this chord is __________ .

The focal chord to y^(2)=16x is tangent to (x-6)^(2)+y^(2)=2 then the possible values of the slope of this chord

The focal chord of y^(2)=16x is tangent to (x-6)^(2)+y^(2)=2 then the possible values of the slope of this chord are

If a focal chord of y ^(2)=16x is a tangent to (x-6)^(2) +y^(2) =2,. then the possible values of the slopes of the chord are-

The focal chord of y^2= 16x is tangent to (x-6)^2+ y^2= 2 , then the possible values of the slope of this chord are :

The focal chord to y^(2)=16x is tangent to (x-6)^(2)+y^(2)=2. Then the possible value of the slope of this chord is {-1,1} (b) {-2,2}{-2,(1)/(2)}(d){2,-(1)/(2)}

The focal chord to y^(2)=16x is tangent to (x-6)^(2)+y^(2)=2, then the possible values of the slope of this chord are: (a) {-1,1} (b) {-2,2}(c){-2,(1)/(2)}(d){2,-(1)/(2)}

The focal chord to y^2=16 x is tangent to (x-6)^2+y^2=2. Then the possible value of the slope of this chord is {-1,1} (b) {-2,2} {-2,1/2} (d) {2,-1/2}