If `tan alpha+sin alpha=p` and `tan alpha-sin alpha=q` tehn `p^2-q^2=`

If cos alpha + cos 2alpha = p , sin alpha + sin 2alpha = q then eliminate alpha .

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then

If p&q are lengths of perpendicular from the origin x sin alpha+y cos alpha=a sin alpha cos alpha and x cos alpha-y sin alpha=a cos2 alpha, then 4p^(2)+q^(2)

If p & q are lengths of perpendicular from the origin x sin alpha + y cos alpha = a sin alphacos alpha and x cos alpha-y sin alpha = acos 2alpha, then 4p^2 + q^2

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then:

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then:

IF tan alpha = ( sin alpha - cos alpha )/( sin alpha + cos alpha) , then sin alpha + cos alpha is

tan theta = (sin alpha-cos alpha) / (sin alpha + cos alpha)

If cos alpha, sin alpha and cot alpha are in G.P. show that tan^(6)alpha- tan^(2)alpha=1

If A=[[0,-tan alpha2,tan alpha2,tan alpha]] and I is 2xx2 unit matrix,then (I-A)[[cos alpha,sin alphasin alpha,sin alphasin alpha,sin alpha]] is (a) these