यदि `cos alpha=(40)/(41), cos beta=5/13`, तो सिद्ध करें की `sin (alpha-beta)=-(435)/(533)cos(alpha+beta)=92/433`.

If sin alpha=(3)/(5) and cos beta=(9)/(41) find the value of sin(alpha-beta) and cos(alpha+beta)

If sin alpha=(15)/(17) and cos beta=(12)/(13) find the values of sin(alpha+beta),cos(alpha-beta) and tan(alpha+beta)

If cos (alpha+beta)=(4)/(5), sin (alpha-beta)=(5)/(13) and 0 lt alpha, beta lt (pi)/(2) then cos 2 alpha=

(cos alpha + cos beta)/( sin alpha - sin beta) + (sin alpha + sin beta)/( cos alpha - cos beta ) =

If cos alpha + cos beta =0 = sin alpha + sin beta " then " cos (alpha - beta )=

(cos alpha + cos beta) ^ (2) + (sin alpha-sin beta) ^ (2) = 4 (cos ^ (2) (alpha + beta)) / (2)

If cos alpha+cos beta=0=sin alpha+sin beta, then prove that cos2 alpha+cos2 beta=-2cos(alpha+beta)

If cos alpha+cos beta=0=sin alpha+sin beta, then prove that cos2 alpha+cos2 beta=-2cos(alpha+beta)