A proton moves on a circular path of radius `6.6 × 10^(-3)` m in a perpendicular magnetic field of 0.625 tesla. The De broglie wavlength associated with the proton will be :

An alpha - particle moves in a circular path of radius 0.83cm in the presence of a magnetic field of 0.25Wb//m^2 .The de-broglie wavelength associated with the particle will be:

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

An alpha -particle moves in a circular path of radius 1 cm in a uniform magnetic field of 0 .1 25 T . The de-Broglie wavelength associated with the alpha - particle is

An a-particle moves along a circular path of radius 0.83 cm in a magnetic field of 0.25 (Wb//m^2) . The de-Broglie wavelength associated with it will be-

An alpha -particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . What is the de Broglie wavelength associated with the particle?

The momentum of alpha -particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :

The momentum of alpha -particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :