A freely falling body crosses the points A, B and C with velocities v, 2v, 3v. Then AB : AC =

A stone thrown vertically up with velocity v reaches three points A, B and C with velocities v,v/2 and v/4 respectively. Then AB:BC is

A stone thrown vertically up with velocity v reaches three points A, B and C with velocities v,v/2 and v/4 respectively. Then AB:BC is

A stone thrown vertically up with velocity reaches three points A, B and C with velocities v/2, v/4 and v/8 respectively. Then AB:BC is

A freely falling body reaches the ground with a velocity v. what height has it been dropped from ?

A freely falling body has a velocity V after falling through H.The distance it has to fall further,for its velocity to be tripled is

A body of mass m _ 1 moving with an unknown velocity of v _ 1 hati , undergoes a collinear collision with a body of mass m _ 2 moving with a velocity v _ 2 hati . After collision m _ 1 and m _ 2 move with velocities of v _ 3 hati and v _ 4 hati , respectively. If m _ 2 = 0.5 m _ 1 and v _ 3 = 0.5 v _ 1 , then v _ 1 is v _ 4 - (v _ 2 ) / (x ) , where x is _________.

A body freely falling from rest has a velocity v after it falls through a height of h. The distance it has to fall down for its velocity to become 2 v is