If `F(alpha)=|(cos alpha, -sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)|` then ` det F(alpha)=`

If A=[(cos alpha, -sin alpha, 0),(sin alpha, cos alpha,0),(0,0,1)] then A^(-1) is

If A=[(cos alpha, - sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)] then (AdjA)^(T)=

If F(alpha)=[[cos alpha,-sin alpha, 0],[sin alpha, cos alpha, 0],[0,0,1]] , then show that F(alpha) F (beta)= F(alpha + beta) .

Let A_(alpha)=[[cos alpha,-sin alpha,osin alpha,cos alpha,00,0,1]]

If A(alpha, beta) = [(cos alpha, sin alpha, 0),(- sin alpha, cos alpha, 0),(0,0,e^beta)] then A(alpha, beta)^(-1) is equal to a) A(-alpha, -beta) b) A(-alpha,beta) c) A(alpha, - beta) d) A(alpha, beta)

If A(alpha, beta)=[("cos" alpha,sin alpha,0),(-sin alpha,cos alpha,0),(0,0,e^(beta))] , then A(alpha, beta)^(-1) is equal to