If `(1+tan1^(@)) *(1+tan2^(@))*(1+tan3^(@)) …….(1+tan45^(@)) = 2^(n)`, then 'n' is equal to :

(1+tan1^(0))(1+tan2^(0))(1+tan3^(0)).......(1+tan45^(0)) =?

If the value of (1+tan 1^(@))(1+ tan 2^(@)) (1+tan 3^(@)) ……….(1+ tan 45) Is 2^(lambda) , then the sum of the digits of the number lambda is

Let (1+tan1^(ul0))(1+tan2^(ul0))......(1+tan45^(ul0))=2^(k) then k equal to

Prove that (1+tan1^(@))(1+tan2^(@))...(1+tan45^(@))=2^(23)

(1+tan3^(@))(1+tan6^(@))....(1+tan42^(@))(1+tan45^(@)=2^(k) Then find the value of k

( 1-tan ^(2) 45^(@) )/( 1+tan ^(2) 45^(@)) =

( 1-tan ^(2) 45^(@) )/( 1+tan ^(2) 45^(@)) =