What is the percentage strength of a solution of 100 volume `H_(2)O_(2)`?

Explanation

100 volume solution means that 1L of this `H_(2)O_(2)` solution will give 100 L of oxygen at STP
`underset(2xx34g=68g)(2H_(2)O_(2))to2H_(2)O+underset(22.7L" at STP")(O_(2))`
From equation,
22.7 of `O_(2)` at STP is obtained from `H_(2)O_(2)=68g`
100 L of `O_(2)` at STP is obtained from `H_(2)O_(2)=(68)/(22.7)xx100`
`=299.55g//L`
`=30%" "H_(2)O_(2)` solution