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Hydrogen perioxde acts both as an oxidis...

Hydrogen perioxde acts both as an oxidising agent and as reducing agent in alkaline solution towards certain first row transition metal ions. Iiustrate both these properties of `H_(2)O_(2)` using chemical equation.

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The correct Answer is:
oxidising agent
`2Cr(OH)_(3)+4NaOH+3H_(2)O_(2)to2Na_(2)CrO_(4)+8H_(2)O`
Here, `Cr^(+3)` gets oxidised to `Cr^(+6)`
Reducing agent.
`3K_(3)[Fe(CN)_(6)]+2KOH+H_(2)O_(2)to2K_(4)[Fe(CN)_(6)]+2H_(2)O+O_(2)`
Here `Fe^(3+)` gets reduced to `Fe^(2+)`
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