Boron nitride on reacting with steam gives

Options

A. `NH_(3)`
B. `N_(2)O`
C. `Na_(2)BO_(2)`
D. `NO_(2)`

Answer

To determine what boron nitride (BN) produces when it reacts with steam, let's break down the reaction step by step.

### Step 1: Understand the Reactants
Boron nitride (BN) is a compound made of boron and nitrogen. When it reacts with steam (water vapor), we need to consider the conditions under which this reaction occurs.

**Hint:** Identify the reactants involved in the reaction.

### Step 2: Identify the Reaction Conditions
The reaction of boron nitride with steam typically occurs at high temperatures, around 800 degrees Celsius. This is important because it influences the products formed.

**Hint:** Consider the temperature and state of the reactants.

### Step 3: Write the Reaction Equation
The reaction of boron nitride with steam can be represented by the following chemical equation:

\[ 2 \text{BN} + 3 \text{H}_2\text{O} \rightarrow \text{B}_2\text{O}_3 + 2 \text{NH}_3 \]

In this reaction:
- Boron nitride (BN) reacts with water (H₂O).
- The products formed are boron trioxide (B₂O₃) and ammonia (NH₃).

**Hint:** Write the balanced chemical equation for the reaction.

### Step 4: Identify the Products
From the balanced equation, we see that the products of the reaction are:
1. Boron trioxide (B₂O₃)
2. Ammonia gas (NH₃)

**Hint:** List the products formed from the reaction.

### Step 5: Conclusion
Thus, when boron nitride reacts with steam at high temperatures, it produces boron trioxide and ammonia gas.

**Final Answer:** Boron nitride reacts with steam to give boron trioxide (B₂O₃) and ammonia (NH₃).

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