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The E^(0)(M^(2+)//M) value for copper is...

The `E^(0)(M^(2+)//M)` value for copper is positive `(+0.34V)`. What is possibly the reason for this?

Text Solution

Verified by Experts

Reduction potential will depend on
(i) `Cu(s) to Cu(g), DeltaH("atomisation")`
(ii) ` Cu(g) to Cu^(2+),(IE_(1) +IE_(2))`
(iii) `Cu^(2+) overset(H_(2)O) to Cu^(2+), (DeltaH_(Hyd))`
Due to high enthalpy of atomisation and low ` DeltaH_("hydration")` energy `E_(Cu^(+2)//Cu)^(@)` is high .
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