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A compound of a metal ion M^(X+)(z=24) h...

A compound of a metal ion `M^(X+)(z=24)` has a spin only magnetic moment of `sqrt(15)B.M.` . The number of unpaired electrons in the compound are

A

2

B

4

C

5

D

3

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The correct Answer is:
D
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The transition metals and their compounds have paramagnetic properties. This is due to the reason that ions of transition metals have unpaired electrons in (n-1)d orbitals. As the number of unpaired Sc to Mn, the paramagnetic character increases accodingly. From Mn onwards, this character decreases as electrons get paired up. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of unpaired electron (n). It is given as Magnetic moment = sqrt(n(n+2))B.M Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. due to d-d transition in which unpaired electrons from the lower energy d-orbitals are transferred to higher energy d-orbitals. The energy of this transition correspond to the radiation in visibe region. Thus, when white light falls on such a transition metal compound, some light energy corresponding to a particular colour is absorbed and one or more electrons are raised from lower energy set of orbitals to those of higher energy. With the absorption of radiations corresponding to specific colour from the white light, a colour known asd the complementary colour is observed or transmitted. A compound of metal ion M^(x+) (z = 24) has a spin only magnetic moment of sqrt(15)B.M. The number of unpaired electrons in the metal ion of the compound are

A comapound in which a metal ion M^(x+)(Z=25) has a spin only magnetic moment of sqrt24 BM The number of unpaired electrons in the compound and the oxidation state of the metal ion respectively are

A compound in which a metal ion \(M^{x+}\)(Z=25) has a spin only magnetic moment of \(\sqrt{24}\)BM.The number of unpaired electrons in the compound and the oxidation state of the metal ion are respectively.

A compound of metal ion M^(x+) (z=25) has spin only magnetic moment of sqrt(15)B.M. The positive O.S. of the metal is

Magnetic moment of M^(x+) is sqrt(24)BM . The number of unpaired electrons in M^(x+) is.

The spin only magnetic moment of 4.90 B.M. is shown by

The species with spin only magnetic moment of sqrt(24) BM is:

Spin magnetic moment of X^(n+) (Z=26) is sqrt(24) B.M. Hence number of unpaired electrons and value of n respectively are:

AAKASH INSTITUTE-THE D AND F-BLOCK ELEMENTS -Assingnment(Section -A ( Objective Type Questions)(One option is correct))
  1. Electrode potential of Mn^(2+)//M for Ni is abnormal because of

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  2. The species which is paramagnetic

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  3. A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment...

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  4. The species which convert Cu^(2+) to Cu^(+)

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  5. Which of the following is not a condition for complex formation?

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  6. Brass is an alloy of

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  7. In acidic medium one mole of MnO(4)^(-) accepts how many moles of elec...

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  8. In the dichromate dianion,

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  9. Which of the following oxide is acidic in nature ?

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  10. The inner transition element that is radioactive is

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  11. The lanthanide contraction is responsible for the fact that

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  12. Size of lanthanoid decrease becaue of poor screening of

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  13. The strongest base is

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  14. The element that is not present in misch metal is

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  15. Most stable oxidation state of Lanthanoids

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  16. When intimate mixture of potassium dichromate and potassium chloride i...

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  17. Which one of the following pairs of ions have the same electronic conf...

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  18. Cr(2)O(7)^(2-)+Xoverset(H^(o+))rarrCr^(3+)+H(2)O+ "oxidised product" o...

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  19. The reducing nature of any metal in aqueous solution depends upon a...

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  20. Which of the following oxide is basic ?

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