A

A is NaOH and B is `NH_(4)OH`

B

Both `Cu(OH)_(2) and [Cu(NH_(3))_(4)]SO_(4)` are pale blue precipitates

C

Blue colour of solution is due to d-d- transition

D

`Cu(OH)_(2)` is paramagnetic and `[Cu(NH_(3))_(4)]^(2+)` is diamagnetic

Text Solution

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The correct Answer is:
A, B, C
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