`(dy)/(dx) + ycotx = 2cos x`

Solve the differential equation: (dy)/(dx)+ycotx=2cosx

The general solution of the differentia equation (dy)/(dx)+ycotx = cos e c x , is (a). x+y \ sin\x=C (b). x+y cos\ x=C (c). y+x(sin x+cos x)=C (d). y \ sinx=x+C

Solve the following initial value problem: (dy)/(dx)+\ ycotx=4x\ cosec x , \ y(pi/2)=0

Solve the differential equation : (dy)/(dx) -3ycotx = sin 2x , given y=2, when x=pi/2

For the differential equation, find a particular solution satisfying the given condition: (dy)/(dx) - 3ycotx = sin2x, y = 2 when x = pi/2

General solution (GS) of (dy)/(dx)+y.cotx=cosx is

Solve the following differential equation: (dy)/(dx)+ycotx=4x\ cos e c\ x ,\ \ given that y=0 when x=pi/2

Solve the differential equation (dy)/(dx)+ycotx=2cosx , given that y=0, when x=pi/2dot

Find the particular solution of the differential equation. (dy)/(dx)+ycotx=4x\ \ cos e c\ x ,\ (x!=0),\ given that y=0 when x=pi/2dot