A valuable piece of stone whose price is rs 15600 breaks into three pieces whose weights are in the ratio 2:3:5 . If the value of the stone varies as the cube of its weights , find the percentage of loss due to breaking .

A diamond worth Rs 640000 breaks into two pices whose weights are in the ratio 5:3. if the value of the diamond varies directly with square of its weight, then find loss incurred due to breakage (in Rs).

A diamond falls and breaks into three pieces whose weights are in the ratio 1 : 3 : 6. The value of the diamond is proportional to the square of its weight. If the original value is '30,000 What is the loss in the in the value due to the breakage?

The price of a diamond is rs 2000 . The diamond is broken into to equal weights . If the price of a diamond varies as the square of its weights , then find the amound of loss for the breakage.

Find three numbers in the ratio 2:3:5, the sum of whose squares is 608.

A diamond falls and breaks into pieces whose weights are in the ratio 2 : 3 : 5 . The value of the diamond is directly proportional to the square of its weight. Find the loss incurred, if the actual cost of the diamond is Rs. 96, 000 . (in Rs.)

The cost of a precious stone varies as the cube of its weight. The stone broke into 3 pieces whose weights are in the ratio 1 : 2 : 3 . As a result its cost reduces . If the cost of the unbroken stone is Rs. 96, 336, then find the loss incurred due to breakage.

A piece of diamond is broken into three pieces, the weights of the pieces being in the ratio 1: 2:3 . Price of a piece of diamond is proportional to the square of its weight . Find the price of the original piece , if the loss due to breakage is rs 22000 .

The value of diamond varies as the square of its weight . A diamond broke into three pieces whose weights are in the ratio 3:4:5 . For this there is a loss rs 9400. Find the value of the original diamond .