ABC and DBC are two triangle on the same base BC such that A and D lie on the opposite sides of BC,AB=AC and DB =DC ,Show that AD is the perpedicular bisector of BC.

In Figure,ABC and DBC are two triangles on the same base BC such that AB=AC and DB=DC .Prove that /_ABD=/_ACD

In Figure,ABC and DBC are two isosceles triangles on the same base BC such that AB=AC and DB=CD. Prove that /_ABD=/_ACD

ABC and DBC are both isosceles triangles on a common base BC such that A and D lie on the same side of BC .Are triangles ADB and ADC congruent? Which condition do you use? If /_BAC=40^(@) and /_BDC=100^(@) ; then find /_ADB

In Delta ABC, AB =AC and D is a piont in side BC such that AD bisect angle BAC. Show that AD is perpendicular bisector of side BC.

Triangles ABC and DBC are two isosceles triangles on the same base BC and their vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that: Delta ABP ~= Delta ACP

Triangles ABC and DBC are two isosceles triangles on the same base BC and their vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that: AP bisects angle BAC and BDC.

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

Delta ABC and Delta DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at E show that

In the adjoining figure, triangle ABC and triangleDBC are on the same base BC with A and D on opposite sides of BC such that ar(triangleABC)=ar(triangleDBC) . Show that BC bisect AD.