PQRS is a square of side 'b'. Prove that the equation of circumcircle of square PQRS, where PQ and PS are the axes, is `x^(2)+y^(2)=b(x+y)`.

Equation of circumcircle of square OACB of side a, where OA and OB are along coordinate axes , is

The sides of a square are x=4, x=7, y=1, y=4 . Then the equation of the circumcircle of the square is

ABCD is a square in first quadrant whose side is a,taking AB and AD as axes,prove that the equation to the circle circumscribing the square is x^(2)+y^(2)=a(x+y)

ABCD is a square of side 'a'. If AB and AD are taken as co-ordinate axes, prove that the equation of the circle circumscribing the square is x^2+y^2=a(x+y) .

The sides of a square are x =4, x = 7, y =1 and y = 4 . The equation of the circumcircle of the square is :

The sides of a square are x =4, x = 7, y =1 and y = 4 . The equation of the circumcircle of the square is :

ABCD is a square in first quadrant whose side is a, taking AB and AD as axes, prove that the equation to the circle circumscribing the square is x^2+ y^2= a(x + y) .

The equation of the circumcircle of the triangle,the equation of whose sides are y=x,y=2x,y=3x+2, is

find (a) the area (b) the perimeter of the square PQRS, if the side is 20 cm.