The locus of the centre of the circle for which one end of the diameter is (3,3) while the other end lies on the line x+y=4 is

The locus of the centre of the cicle for which one end of a diamert is (1.) while the other end is one the line

The centre of the circle is (2,1) and one end of the diameter is (3,-4). Another end of the diameter is……….

The centre of the circle is (2, 1) and one end of the dimameter is (3 , -4) .An-ohther end of thi diameter is …….

The centre of a cirlce is (-4,2) . If one end of the diameter of the circle is (-3,7) tehn find the other end.

If one end of a diameter of a circle is (3,5) and the centre is (2,3) then the other end of the diameter is

If one end of the diameter is (1,1) and other end lies on the line x+y=3 , then locus of centre of circle is

One end of the diameter of a circle with the centre as origin is (-2 ,10) . Find the other end of the diameter

If the centre of a circle is (3,5) and end points of a diameter are (4,7) and (2,y) then the value of y is:

The coordinate of one end of a diameter of a circle is (3, 3) and its other end is on the line x+y = 4. If the equation of locus of its centre is x+y = k, then value of k is -

If one end of the diameter of the circle x^2 + y^2 - 8x - 4y + c = 0 is (-3, 2), then the other end is :