यदि समीकरण निकाय `3x + y =1` और `(2k -1)k +(k-1)y = 2k +1` असग्त है तो k का मान ज्ञात कीजिए ।

( k - 1 ) x - y = 5 , (k + 1 ) x + ( 1 - k ) y = ( 3k + 1 )

यदि (x/3+1,y-2/3) = (5/3,1/3) हो, तो x और y का माना ज्ञात , कीजिये।

5x + 2y = 2k , 2 (k + 1 ) x + ky = (3k + 4)

{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = 2(k - 1)):}

{:(2x + (k - 2)y = k),(6x + (2k - 1) y = 2k + 5):}

The pair of equations 3x+y=1 (2k-1)x+(k-1)y=2k+1 is consistent for what value of k?

The value of k for which the graph of (k- 1)x+ y-2= 0 and (2-k)x-3y+ 1) =0 are parallel is k का मान जिसके लिए (k- 1)x+ y-2= 0 और (2-k)x-3y+ 1) =0 के ग्राफ समांतर हो, है-

det [[x ^ (k), x ^ (k + 2), x ^ (k + 3) y ^ (k), y ^ (k + 2), y ^ (k + 3) z ^ (k) , z ^ (k + 2), z ^ (k + 3)]] = (xy) (yz) (zx) {(1) / (x) + (1) / (y) + (1) / ( from)}

If the system of equations 3x+y=1,\ \ (2k-1)x+(k-1)y=2k+1 is inconsistent, then k=