`x/4+y/5 =22 ,
x/5+y/4 =23`

(x) / (4) + (y) / (5) + 1 = 23, (x) / (5) + (y) / (4) = 23

If 2x + y = 23 and 4x - y = 19 , then find the values of 5y - 2x and (y)/(x) - 2 .

If 2x + y = 23 and 4x - y = 19 , then find the values of 5y - 2x and (y)/(x) - 2 .

If 2x + y = 23 and 4x - y = 19, find the values of x - 3y and 5y - 2x.

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

The straight lines x + y = 0 , 5 x + y = 4 and x + 5y = 4 form _