The amount of heat supplied to decrease the volume of an ice water mixture by `1 cm^(3)` without any change in temperature, is equal to: `(rho_("ice") = 0.9, rho_("water") = 80 cal//gm)`

The amount of heat required to change 1 gm (0^(@)C) of ice into water of 100^(@)C , is

Calculate the quantity of heat released during the conversion of10g of ice cold water ( temperature 0^(@)C ) into ice at the same temperature . ( Specific latent heat of freezing of water = 80 cal //g )

Calculate the quantity of heat released during the conversion of 10g of ice cold water (temperature 0⁰C ) into ice at the same temperature. (Specific latent heat of fusion of ice = 80 cal/g)

The amount of heat required to raise the temperature of 75 kg of ice at 0^oC to water at 10^oC is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/ g^oC )

Calculate the amount of heat required to convert 80 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the amount of heat required to convert 80g of ice at 0^(@)C into water at the same temperature . ( Specific latent heat of fusion of ice = 80 cal //g )

The amount of heat required to raise the temperature of 75 kg of ice at 0°C to water at 10°C is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/g °C)

540 gm of ice at 0^@ is mixed with 540 gm of water at 80^@C . The final temperature of the mixture is