The solution of 2.5 g of a non-volatile substance in 100 g of benzene boiled at a temperature `0.42^(@)C` higher than the b.p. of pure benzene. Calculate mol. Wt. of the substance. (`K_(b)` of benzene is 2.67 K kg `"mole"^(-1)`)

A solution of 2.5g of non-volatile solid in 100g benzene is boiled at 0.42^(@)C higher than the boiling point of pure benzene. Calculate the molecular mass of the substance. Molal elevation constant of benzene is 2.67 "K kg mol"^(-1) .

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

If solution containing 0.15 g of solute dissolved in 15 g of solvent boils at a temperature higher by 0.216^(@)C than that of pure solvent, the molecular mass of the substance is (K_(b)=2.16^(@)C)

Boiling point of benzene is 353.23 K . When 1 . 80 g of non-volatile solute was dissolved in 90 g of benzene the boiling point is raised to 354. 11 K? Calculate molar mass of solute . ( K_(b) for benzene is 2 . 53 K kg mol^(-1) )