[[sin20^(0),-cos20^(@)],[sin70,cos70]]=?

Write the value of |[sin20^@-cos20^@ ],[sin70^@ cos70^@]| .

sec70^(@)sin20^(@)+cos20^(@)"cosec"70^(@)=?

The value of (sin 20^(@) cos 70^(@)+sin70^(@) cos 20^(@) ) is ……….. .

sec70^(@)sin20^(@)+cos20^(@)cosec70^(@)=2

sin 70^@ - cos 40^(@) =

|["cos"70^(@), "sin"20^(@)], ["sin"70^(@), "cos"20^(@)]|=?

cos70^(@)+sin40^(@)=

cos70^(@)+sin40^(@)=

The value of (sin 20^(@)cos70^(@)+ cos20^(@)sin70^(@))/(sin23^(@)"cosec"23^(@)+cos23^(@)sec23^(@)) is _________.

Without using trigonometric tables, prove that sec70^(@)sin 20^(@) + cos 20^(@) cosec 70^(@)=2 .