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prove that sqrt2,sqrt3,sqrt5 cannot be t...

prove that `sqrt2,sqrt3,sqrt5` cannot be the terms Of an arithmetic progression.

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Prove that the numbers sqrt2,sqrt3,sqrt5 cannot be three terms (not necessarily consecutive) of an AP.

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If p,q and r ( pneq ) are terms ( not necessarily consecutive) of an A.P., then prove that there exists a rational number k such that (r-q)/(q-p) =k. hence, prove that the numbers sqrt2,sqrt3 and sqrt5 cannot be the terms of a single A.P. with non-zero common difference.

If p,q and r ( pneq ) are terms ( not necessarily consecutive) of an A.P., then prove that there exists a rational number k such that (r-q)/(q-p) =k. hence, prove that the numbers sqrt2,sqrt3 and sqrt5 cannot be the terms of a single A.P. with non-zero common difference.

If p,q and r ( pneq ) are terms ( not necessarily consecutive) of an A.P., then prove that there exists a rational number k such that (r-q)/(q-p) =k. hence, prove that the numbers sqrt2,sqrt3 and sqrt5 cannot be the terms of a single A.P. with non-zero common difference.

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Is the sequence sqrt(3), sqrt(6), sqrt(9), sqrt(12) ,…… form an Arithmetic Progression ? Give reason.