" 8."(dy)/(dx)+y=1,(y!=1)...

" 8."(dy)/(dx)+y=1,(y!=1)

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" (b) Solve "(dy)/(dx)+y=1,y!=1

Solve the equation: (dy)/(dx)+y=1, y!=1

Integrate the following: (dy)/(dx)+y=1, (y ne 1)

If y^x=x^y then (dy)/(dx) at x=1, y=1 is

The solution of (dy)/(dx)-y=1, y(0)=1 is given by

The solution of (dy)/(dx)-y=1, y(0)=1 is given by

y(dy)/(dx)=1+y^(2)

"If "y=e^(x+y)" ,show that "(dy)/(dx)=(y)/(1-y)

Solve: (dy)/(dx)+y=1

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