" 24."|(2x-1)/(x-1)|>2,x in R

Solve: |(2x-1)/(x-1)|gt2,x in R

(x+1)/3le(2x-1)/4,x in R

Solve: (-1)/(|x|-2)>=1, where x in R,x!=+-2

Let f(x)={(x^4-5x^2+4)/(|(x-1)(x-2)| , x!=1,2 & 6, x=1 & 12 , x = 2 then f(x) is continuous on the set (a) R (b) R-{1} (c) R-{2} (d) R-{1,2}

Let f : R to R be such that, f(2x-1)=f(x) for all x in R . If f is continuous at x = 1 and f(1)=1 then-

Solve : 2|x+1|^(2)-|x+1|=3 , x in R

Solve : 2|x+1|^(2)-|x+1|=3 , x in R

L e tf(x)={(x^4-5x^2+4)/(|(x-1)(x-2)6),x!=1,2 12,x=2x=1 then f(x) is continuous on the set R (b) R-[1] (c) R-[2] (d) R-[1,2]

Let f : R-{1} to R be defined by f(x) =(1+x)/(1-x) AA x in R -{1} then for x ne +-1, (1+f(x)^(2))/(f(x)f(x^(2))) =………….