Prove that :`1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6`

Prove the following by the principle of mathematical induction: 1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6

Prove the following by the principle of mathematical induction: 1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6

Prove the following by the principle of mathematical induction: 1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6

For all n gt= 1 , prove that, 1^2 + 2^2 + 3^2 + 4^2 + …….+n^2 = (n(n+1)(2n+1))/(6)

Consider the statement P(n):1^2+2^2+3^2+…….+n^2-(n(n+1)(2n+1))/6 By assume that P(k) is true, prove that P(k+1) is true.

Prove the following by the principle of mathematical induction: 1^(2)+2^(2)+3^(2)++n^(2)=(n(n+1)(2n+1))/(6)

Prove the following by the method of induction for all n in N : 1^2 + 2^2 + 3^2 + ... + n^2 = (n(n + 1) (2n + 1)) / 6 .

By ........in "Principle of Mathematical Induction" prove that for all n in N 1^2+2^2+3^2+.......+n^2=(n(n+1)(2n+1))/(6)

Prove that :1+2+3+...+n=(n(n+1))/(2)

Prove the following by induction. 1^2 + 2^2 + ….+ n^2 = n(n+1)(2n+1)//6