At what height from the surface of earth will the value of `g` becomes `40%` from the value at the surface of earth. Take radius of the earth `= 6.4 xx 10^(6) m`.

At what height from the surface of earth will the value of g be reduced by 36% from the value on the surface? Take radius of earth R = 6400 km .

At what height from the surface of earth will the value of g be reduced by 36% from the value on the surface? Take radius of earth R = 6400 km .

At what height above the earth's surface does the value of g becomes 36% of the value at the surface of earth ?

At what height above the earth's surface does the value of g becomes 36% of the value at the surface of earth ?

At what depth from the surface of earth, the value of acceleration due to gravity is reduced by 40% of its value on the surface of earth. Radius of the earth = 6.4 xx 10^(6) m .

At what height from Earth's surface the acceleration due to gravity becomes 20% of its value on the surface of earth. [Radius of earth = 6,400 km.]

How much below the surface of Earth does the acceleration due to gravity become 70% of its value on the surface of Earth. Radius of Earth = 6.4 xx 10^(6) m .

At what height above the surface of earth the value of "g" decreases by 2 % [ radius of the earth is 6400 km ]