If `A=[[1, 0],[0, 1]]`, then

If A=[[0,1],[1,0]] , then A^2 is equal to: (a) [[0,1],[1,0]] (b) [[1,0],[0,1]] (c) [[1,0],[1,0]] (d) [[0,0],[1,1]]

If A=[[0, 1, 0], [1, 0, 0], [0, 0, 1]] , then A^(-1)=

If A = [[1,0],[0,-1]] and B=[[0,1],[1,0]] , then AB = [[0,1],[-1,0]] and BA = [[0,-1],[1,0]] . Clearly AB ne BA Thus matrix multiplication is not commutative.

If A=[[1,0],[0,1]],B=[[1,0],[0,-1]] and C=[[0,1],[1,0]] then show that A^(2)=B^(2)=C^(2)

If A=[[0,-1,0],[1,0,0],[0,0,-1]] , then A^(-1) is

If A = [[1,1,0],[0,1,0],[1,0,1]] then A^(3) =

If A=[[1,0,1],[0,1,1],[1,0,0]] then A^-1 is

If A = [ [ 0 , 1 ] , [ 0 , 1 ] ] ,then A^2 is equal to ( a ) [ [ 0 , 1 ] , [ 1 , 0 ] ] ( b ) [ [ 1 , 0 ] , [ 1 , 0 ] ] ( c ) [ [ 0 , 1 ] , [ 0 , 1 ] ] ( d ) [ [ 1 , 0 ] , [ 0 , 1 ] ]

If A=[[1,0,1],[0,1,1],[1,0,0]], then |A| is