" (घ) हल कीजिए ":sin^(-1)x+tan^(-1)x=pi/2

निम्न समीकरण को हल कीजिए - tan^(-1)(x-1)+tan^(-1)(x)+tan^(-1)(x+1)=tan^(-1) 3 x

If sin^(-1)x + tan ^(-1) x = (pi)/(2) , then prove that 2x^(2) + 1 = sqrt(5)

If sin^(-1)x + tan ^(-1) x = (pi)/(2) , then prove that 2x^(2) + 1 = sqrt(5)

If A = (1)/(pi) [{:(sin^(-1)(pix),, tan^(-1)((x)/(pi))),(sin^(-1)((x)/(pi)),,cot^(-1)((x)/(pi))):}] B = (1)/(pi) [{:(-cos^(-1)(pix),, tan^(-1)((x)/(pi))),(sin^(-1)((x)/(pi)),,-tan^(-1)((x)/(pi))):}] then A - B is equal to

If A = 1/pi [(sin^(-1)(xpi),tan^(-1)(x/pi)),(sin^(-1)(x/pi),cot^(-1)(pix))] B = 1/pi [(-cos^(-1)(xpi),tan^(-1)(x/pi)),(sin^(-1)(x/pi),-tan^(-1)(pix))] then A-B is equal to :

Given that , tan^(-1) ((2x)/(1-x^(2))) = {{:(2 tan^(-1) x"," |x| le 1),(-pi +2 tan^(-1)x","x gt 1),(pi+2 tan^(-1)x"," x lt -1):} sin^(-1)((2x)/(1+x^(2))) ={{:(2 tan^(-1)x","|x|le1),(pi -2 tan^(-1)x","x gt 1 and ),(-(pi+2tan^(-1))","x lt -1):} sin^(-1) x + cos^(-1) x = pi//2 " for " - 1 le x le 1 sin^(-1) ((4x)/(x^(2)+4)) + 2 tan^(-1)( - x/2) is independent of x , then