If the electron gain enthalpy of S and Se are `-200` KJ `" mol"^(-1)` and `-195 KJ " mol"^(-1)` respectively. Wha is the electron gain enthalpy of O atom?

Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ"mol"^(-1) and 4kJ"mol"^(-1) respectively. The hydration enthalpy of NaCl is

Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ"mol"^(-1) and 4kJ"mol"^(-1) respectively. The hydration enthalpy of NaCl is

If the ionization enthalpy and electron gain enthalpy of an element are 275 and 86 kcal mol^(-1) respectively, then the electronegativity of the element on the Pauling scale is

If the ionisation enthalpy and electron gain enthalpy of an element are 275 and 86 kcal mol^(-1) respectively, then the electronegativity of the element on the pauling scale is:

If the ionization enthalpy and electron gain enthalpy of an element are 275 and 86 kcal mol^(-1) respectively, then the electronegativity of the element on the Pauling scale is

The enthalpies of formation of CO and CO_(2) are -110.5 KJ mol^(-1) and -393.5 KJ mol^(-1) respectively. The enthalpy of combustion of carbon monoxide is

Knowing the electron gain enthalpy values for O to O^(-) " and " O to O^(2-) " as " -141 " kJ mol"^(-1) " and " 702 " kJ mol"^(-1) respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^(-) ?