A series LCR circuit is connected across a source of emf E `= 20 sin (100pit - pi/6)`. The current from the supply is I `= 4sin (100pit + pi/12)`. Draw the impedance triangle for the circuit.

A series LCR circuit is connected across a source of emf E =10 sin (100 pi l - pi /6) . The current from the supply si l = 2 sin (100 pi l + pi/12) . Draw the impedance triangle for the circuit.

A series L-C-R circuit is connected across an AC source E = 10sin[100pit - pi/6] . Current from the supply is I = 2sin[100pit + pi/12] , What is the average power dissipated?

A series L-C-R circuit is connected across an AC source E = 10sin[100pit - pi/6] . Current from the supply is I = 2sin[100pit + pi/12] , What is the average power dissipated?

A series L-C-R circuit is connected across an AC source V = 10sin[100pit - pi/6] . Current from the supply is I = 2sin[100pit + pi/12] , What is the average power dissipated?

A resistor and an inductor are connected in series to an AC source of voltage 150 sin (100 pit +pi) volt. If the current in the circuit is 5 sin (100 pit + (2pi)/(3)) ampere then the average power dissipated and the resistance of the resistor are respectively

An inductor 2//pi Henry, a capacitor 100//T muF and a resistor 75Omega are connected in series across a source of emf V=10sin 100pit . Here t is in second. (a) find the impedance of the circuit. (b) find the energy dissipated in the circuit in 20 minutes.

An inductor 2//pi Henry, a capacitor 100//T muF and a resistor 75Omega are connected in series across a source of emf V=10sin 100pit . Here t is in second. (a) find the impedance of the circuit. (b) find the energy dissipated in the circuit in 20 minutes.

The series combination of resistance R and inductance L is connected to an alternating source of e.m.f. e = 311 sin (100 pit) . If the value of wattless current is 0.5A and the impedance of the circuit is 311Omega , the power factor will be –

A capacitor of 2 muF is connected to an AC source of emf e = 250 sin 100 pit . Write an equation for instantaneous current through the circuit and give reading of AC ammeter connected in the circuit.