In Thomson mass spectrograph `vecE bot vecB` then the velocity of underflected electron beam will be :

In order to coincide the parabolas formed by singly ionized ions in one spectrograph and doubly ionized ions in the other Thomson's mass spectrograph , the electric fields and magnetic fields are kept in the ratios 1 : 2 and 3 : 2 respectively . Then the ratio of masses of the ions is

If an electron is going in the direction of magnetic field vecB with the velocity of vecv then the force on electron is

In Thomson's experiment to determine e/m of an electron, it is found that an electron beam having kinetic energy of 45.5 eV remains undeflected, when subjected to crossed electric and magnetic fields. If E=1xx10^(3)Vm^(-1) , the value of B is (mass of the electron is 9.1xx10^(-31)kg )

In Thomson.s experiment, prove that the ratio of charge to the mass (e/m) of an electron is given by : (e)/(m)=(1)/(2V).(E^(2))/(B^(2)) where the terms have their usual meaning.

In a certain region of space electric field vecE and magnetic field vecB are perpendicular to each other and an electron enters in region perpendicular to the direction of vecB and vecE both and move underflected, then velocity of electron is

In a certain region of space electric field vecE and magnetic field vecB are perpendicular to each other and an electron enters in region perpendicular to the direction of vecB and vecE both and move underflected, then velocity of electron is

How are electric vector (vecE) , magnetic vector (vecB) velocity vector (vecC) oriented in an electromagnetic wave?

How are electric vector (vecE), magnetic vector (vecB) velocity vector (vecc) oriented in an electromagnetic wave?

A beam of electrons is moving with uniform velocity in a region having transverse uniform electric and magnetic field of strength. 100 V/m and 0.1 T respectively at right angles to the direction of beam. The velocity of the electrons is