[f(x)={[5," uten "x leqslant],[ax+b,2

" If the function "f(x)=x^(2)+bx+3" is not injective for values of "x" in the interval "0leqslant x leqslant1" then "b" lies in "

If f(x) is continuous at x=2 and x=10 , where f(x)={:{(5", if " x le 2),(ax+b", if " 2 lt x lt 10),(21", if " x ge 10):} , then

Determine the constants 'a' and 'b' so that the function 'f' defined below is continuous everywhere : f(x)={{:(x+2", "xle2),(ax+b", "2ltxlt5),(3x-2", "xge5):} .

Find the values of a and b such that the function defined as follows is continuous : f(x)={{:(x+2,x le2),(ax+b,2 lt x lt 5),(3x-2, x ge 5):} .

Let the function f(x)={1, if x<=3 and ax+b, if 3

If f(x) = ax + b and f(0) = 3, f(2) = 5, then find the value of a and b.

If f((ax+b)/(x-a))=x, then f^(-1)(x)= (a) x (b) (bx+a)/(x-b)( c) f(x)

Determine the constants 'a' and 'b' so that the function 'f' defined below is continuous everywhere: f(x) = {:{(x+2,xle2),(ax+b,2 < x<5),(3x-2,xge5):}

If f(x) is derivable at x =2, where f(x) ={{:( x^(2),"for" xle 2 ),( ax + b,"for " xgt2 ):},then

The function f(x) Is defined as follows : f(x)={{:(x^(2)+ax+b" , "0lexlt2),(3x+2" , "2lexle4),(2ax+5b" , "4ltxle8):} . If f(x) is continuous on [0,8], find the values of 'a' and 'b'.