[" र्देश : ज्ञात कीजिए कि निम्नलिखित रेखाएँ प्रतिच्छेद करती है "],[" थवा नहीं : "],[qquad (x-1)/(2)=(y+1)/(3)=z" तथा "(x+1)/(5)=(y-2)/(1),z=2]

The lines (x-1)/(3) = (y+1)/(2) = (z-1)/(5) and x= (y-1)/(3) = (z+1)/(-2)

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3) and (x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3)and(x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

(2-3x)/(x)+(2-3y)/(y)+(2-3z)/(z)=0 then (1)/(x)+(1)/(y)+(1)/(z)=

The lines x/2=y/1=z/3 and (x-2)/(2)=(y+1)/(1)=(3-z)/(-3) are ….

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

If x+y+z=xyz , prove that x/(1-x^2)+ y/(1-y^2)+z/(1-z^2) =(4xyz)/((1-x^2)(1-y^2)(1-z^2))

Prove that |(1,x,x^2),(1,y,y^2),(1,z,z^2)| = (x-y)(y-z)(z-x)

If x y+y z+x z=1 ,then prove that x/(1-x^2)+y/(1-y^2)+z/(1-z^2)=(4x y z)/((1-x^2)(1-y^2)(1-z^2)

If x y+y z+x z=1 ,then prove that x/(1-x^2)+y/(1-y^2)+z/(1-z^2)=(4x y z)/((1-x^2)(1-y^2)(1-z^2)