In the figure shown ,find :`(g = 10 m//s^(2))`

(a) acceleration of `1 kg,2 kg` and `3 kg` blocks and
(b) tension `T_(1)` and `T_(2)`.

In the figure ( g = 10 m//s^(2) ) .Acceleration of 2kg block is :

In the arrangment shown pulley is ideal and string is massless. 5kg block is moving on the smooth surface. When theta is 37^(@) , then acceleration of 5kg and 10 kg blocks are a_(1) and a_(2) while tension in string is T then : ( g =10 m//s^(2) ) :

In the figure shown, m_(1) = 10kg, m_(2) = 6kg, m_(3) = 4kg. If T_(3) = 40 N, T_(2) = ?

In the figure shown, m_(1) = 10kg, m_(2) = 6kg, m_(3) = 4kg. If T_(3) = 40 N, T_(2) = ?

Three blocks are connected as shown in on a horizontal frictionless table and pulled to the right with a force F = 60N. If m_(1) = 5 kg, m_(2) = 10 kg and m_(3) = 15 kg, Find the tension T_(1) and T_(2) .

In the adjacent figure, masses of A,B and C are 1kg ,3kg and 2kg respectively. Find (a) the acceleration of the system and (b) tension in the strings. Neglect friction. (g=10m//s^(2))

In the abjecent figure, masses of A,B and C are 1kg ,3kg and 2kg respectivelly.Find (a) the acceleration of the system and (b) tension in the strings. Neglect friction. (g=10m//s^(2))

Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in figure. The whole system is going upwards with an acceleration of 2m s^(-2) . The tensions T_(1) and T(2) are respectively ("Take g"=10ms^(-2))

In figure shown if m_(A) = 20 kg and m_(B) = 80 kg. The acceleration of block A if the system is set free to move is beta m//s^(2) . Find the value of beta . (Take g = 10 ms^(-2) )