[" If "|" ( "1" ,then "],[" Lt "(1+x)(1+x^(2))(1+x^(4))...(1+x^(2n))=]

If |x| lt 1" thn "underset(n to oo)"Lt "(1+x)(1+x^(2))(1+x^(4))....(1+x^(2n))=

if |x| oo)(1+x)(1+x^2)(1+x^4)........(1+x^(2n))=

if |x|<1 then (Lt)_(n rarr oo)(1+x)(1+x^(2))(1+x^(4))......*(1+x^(2n))=

If |x| lt 1 , then (1)/(2) log((1+x)/(1-x))=

If |x| lt 1, then 1/2 log ((1+x)/(1-x)) =

Lt_(x to 0)((1+x^(2))^(1//3)-(1-2x)^(1//4))/(x+x^(2))

If x lt 1 , then 1/(x + 1) + (2x)/(1 +x^2) + (4x^3)/(1 + x^4) + ….oo =

If y=lim_(nrarroo)(1+x)(1+x^(2))(1+x^(4))...(1+x^(2n))andx^(2)lt1 , then y' is equal to a)1 b) (1)/(1-x) c) (1)/(1+x) d) (-1)/((1-x)^(2))