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The following are the steps involved in finding the least amont `sqrt(3),root(3)(4) and root(6)(15)` . Arrange them in sequential order.
(A) `therefore root(6)(15)` is the smallest
(B) `therefore 3^(1//2)=3^(3//6), 4^(1//3)=4^(2//6), 15^(1//6)=15^(1//6)`
(C)The LCM fo the denominators of the exponents is 6
(D) `sqrt(3)=3^(1//2), root(3)(4)=4^(1//3), root(6)(15)=15^(1//6)`
(E) `therefore sqrt(3)=root(6)(27), root(3)(4)=root(6)(16)root(6)(15)=root(6)(15)`

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The following are the steps involved in finding the greatest among root(3)(2),root(6)(3) and sqrt(6) . Arrange them in sequential order. (A) The LCM of the denominators of the exponents is 6. (B) therefore root(6)(216) i.e., sqrt(6) is greatest. (C) root(3)(2)=2^(1//3), root(6)(3)=3^(1//6), sqrt(6)=6^(1//2) (D) 2^(1//3)=2^(2//6), 3^(1//6), 6^(1//2)=6^(3//6) (E) root(3)(2)=root(6)(4)root(6)(3)-root(6)(3),sqrt(6)=root(6)(216)