Home
Class 11
PHYSICS
According to kepler's law of periods, T^...

According to kepler's law of periods, `T^(2) = k r^(3)`, where `k` is a constant. Compute the constant `k` for (a) the earth and (b) the venus. Given that orbital radii of the earth and the venus are `1.496 xx 10^(11) m` and `1.082 xx 10^(11) m`, and their respective periods are 1 year and `0.615` year.

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the mass of the sun if the mean orbital radius of Jupiter around the sun is 7.8 xx 10^(11) m . Take G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) Time period of revolution = 12 years according to earth

Calculate the mass of the sun , given that the sistance between the sum and the earth is 1.5xx 10^(-11) m and G = 6.66 xx 10 ^(-11) SI units and taken a year = 365 days .

Estimate the mass of the sun, assuming the orbit of the earth round the sun to be a circle. The distance between the sun and earth is 1.49 xx 10^(11) m and G = 6.66 × 10^(-11) Nm^(2)//kg^(2) .

How fast (in m^(2) s^(-1)) is area swept out by (a) the radius from sun to earth ? (b) the radius from the sun to earth = 1.496 xx 10^(11) m , Distance of earth to moon = 3.845 xx 10^(8) m and period of revolution of moon = 27 (1)/(3) days.

Assuming that earth's orbit around the sun is a circle of radius R=1.496xx10^(11)m compute the mass of the sun. (G=6.668xx10^(-11)Nm^(2)kg^(-2))

The time period of jupiter is 11-6 year, how far is jupitor from the sun. Distance of earth from the sun is 1.5 xx 10^(11) m .