`triangleABC` तथा `triangle DEF` में, यदि `(AB)/(DE) = (BC)/(FD)'` तम समान कोण का युग्म ज्ञात कीजिए |

If in triangleABC and triangleDEF,(AB)/(DE)=(BC)/(FD) then triangleABC~triangleDEF when

If in triangles ABC and EDF, (AB)/(DE)=(BC)/(FD) then they will be similar, when

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

triangle ABC ~ triangle EDF and ar(triangle ABC) : ar(triangle DEF) = 1:4 . If AB =7cm, BC = 8 cm and CA = 9 cm, then DF is equal to : triangle ABC ~ triangle EDF और ar (triangle ABC) : ar(triangle DEF) = 1: 4 है। यदि AB = 7 सेमी, BC = 8 सेमी तथा CA = 9 सेमी है, तो DF का मान किसके बराबर होगा?

In Delta ABC and Delta DEF is (AB)/(DE) = (BC)/(DF) then they will be similar if:

triangle ABC ~ triangle EDF and ar(triangle ABC) : ar(triangle DEF) = 4 : 9 . If AB = 6 cm, BC = 8 cm and AC = 10 cm, then DF is equal to : triangle ABC ~ triangle EDF और ar(triangle ABC) : ar(triangle DEF) = 4 : 9 है। यदि AB = 6 सेमी, BC = 8 सेमी तथा AC = 10 सेमी है, तो DF का मान क्या होगा ?

Let triangle ABC ~ triangle RPQ and (ar(triangle ABC))/(ar(triangle PQR))= 4/9 , If AB = 3cm, BC=4cm and AC = 5cm, then PQ (in cm ) is equal to : मान लीजिये कि triangle ABC ~ triangle RPQ तथा (ar(triangle ABC))/(ar(triangle PQR))= 4/9 हैं | यदि AB = 3cm, BC=4cm और AC = 5cm है, तो PQ का मान ज्ञात करे:

Let triangle ABC ~ triangle RPQ and (ar(triangle ABC))/(ar(triangle PQR))= 4/9 , If AB = 3cm, BC=4cm and AC = 5cm, then RP (in cm ) is equal to : मान लीजिये कि triangle ABC ~ triangle RPQ तथा (ar(triangle ABC))/(ar(triangle PQR))= 4/9 हैं | यदि AB = 3cm, BC=4cm और AC = 5cm है, तो RP का मान ज्ञात करे: