`f(x)=x^(3)+ax^(2)+bx+c ` parameters ` a,b ,c `are chosen respectively by throwing a die three times,then probability that `f(x)` is non decreasing is.

Consider f(x)=x^(3)+ax^(2)+bx+c , parameters a,b,c are chosen respectively by throwing a dice three times. Then probability that f(x), is an increasing functions is

Suppose f(x)=x^(3)+ax^2+bx+c.a,b,c are chosen respectively by throwing a die three times. Find the probability that f(x) is an increasing function.

Suppose f(x)=x^(3)+ax^2+bx+c.a,b,c are chosen respectively by throwing a die three times. Find the probability that f(x) is an increasing function.

consider f(x)=x^(3)+ax^(2)+bx+c Parameters a,b,c are chosen as the face value of a fair dice by throwing it three xx Then the probability that f(x) is an invertible function is (A) (5)/(36) (B) (8)/(36) (C) (4)/(9) (D) (1)/(3)

Consider f(x) =x^3+ax^2+bx+c Parameters a, b, c are chosen as the face value of a fair dice by throwing it three times Then the probability that f(x) is an invertible function is (A) 5/36 (B) 8/36 (C) 4/9 (D) 1/3

Consider f(x) =x^3+ax^2+bx+c Parameters a, b, c are chosen as the face value of a fair dice by throwing it three times Then the probability that f(x) is an invertible function is (A) 5/36 (B) 8/36 (C) 4/9 (D) 1/3

Consider f(x) =x^3+ax^2+bx+c Parameters a, b, c are chosen as the face value of a fair dice by throwing it three times Then the probability that f(x) is an invertible function is (A) 5/36 (B) 8/36 (C) 4/9 (D) 1/3

Consider f(x) =x^3+ax^2+bx+c Parameters a, b, c are chosen as the face value of a fair dice by throwing it three times Then the probability that f(x) is an invertible function is (A) 5/36 (B) 8/36 (C) 4/9 (D) 1/3

A function f is such that f(x)=x^3+ax^2+bx+c , where a, b, c are chosen by throwing a die three times. The probability that f is an increasing function is